Can we create a View with model in sitecore without creating a Controller?

Pranay

Jan 07, 2015 · 6771 views

Problem: To create an MVC 'View' bound with a 'Model' but without creating any controller in Sitecore MVC 7.2.

###Solution:

We can create a view rendering passing a model to the view without any controller. Follow the below steps to create a sample view passing a custom model without using a controller.

Version used: Sitecore 7.2 with MVC 5.1

Create Model class in C# .NET(LoginModel.cs). This is the model which we are going to pass it to a view.

LoginModel.cs

using System;
using System.Collections.Generic;
using System.Linq;
using System.Web;

namespace Sitecore.MyProjSolution.Website.Models.LoginModel
{
    public class LoginModel
    {
        public string UserName { get; set; }
        public string Password { get; set; } 
    }
}

Create model in Sitecore.
- Go to Layout->Models
- Right click and create a model item with name 'MyModel'
- In the Model type field enter the model class assembly path and namespace path separated by comma as shown below. Sitecore.MyProjSolution.Website.Models.LoginModel,Sitecore.MyProjSolution.Website

Create view rendering in Sitecore

go to layout->Renderings
right click and create a View Rendering. Give some name to the view rendering

After creating the view rendering, under the Data section, assign values to its fields as shown below.

'Path' -> (path to the view file i.e., the .cshtml file):say "Views/Account/Login.cshtml"

Sample Login.cshtml:

  @model Sitecore.MyProjSolution.Website.Models.LoginModel
  <div class="dropdown-menu my-login-dropdown" style="padding:20px;">
      @using (Html.BeginForm("Login", "Account", FormMethod.Post))
      {
          @Html.TextBoxFor(m => m.UserName, new { @class = "form-control", 
                               @Placeholder = "Username" })
          @Html.PasswordFor(m => m.Password, new { @class = "form-control", 
                               @Placeholder = "Password" })
          <input type="submit" id="btnLogin" class="btn btn-default" 
                 value="Submit" />
      }

  </div>

'Model' -> CLick on 'Insert link' and select the sitecore model which we have created in the step 2 i.e, MyModel.

PlaceHolder -> select the placeHolder in which you want to render this view(placeHolder as per the Layout). Say ‘phLogin’.

Below is the a sample layout file(SampleLayout.cshtml).

  <!DOCTYPE html>
  <html lang="en">
      <head>
          <title>Sample Page</title>
      </head>
      <body>
          <div class="header">
              @Html.Sitecore().Placeholder("phHeader")
          </div>

          <div class="Body">
              @Html.Sitecore().Placeholder("phLogin")

          </div>

          <div class="footer">
              @Html.Sitecore().Placeholder("phFooter")
          </div>
      </body>
  </html>

In the above tutorial, just a blank Model class is passed without any data in it. This is normally useful to create Html submit Forms which are bound to Models using the @Html.BeginForm of MVC, but if you want to populate the model at Sitecore and pass that model data to the view go through the below tutorial.

How to pass a Sitecore populated Model from sitecore to a .NET MVC view

AUTHOR